b^2-12b-64=0

Solution for b^2-12b-64=0 equation:

Simplifying
b2 + -12b + -64 = 0

Reorder the terms:
-64 + -12b + b2 = 0

Solving
-64 + -12b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-4 + -1b)(16 + -1b) = 0

Subproblem 1
Set the factor '(-4 + -1b)' equal to zero and attempt to solve:

Simplifying
-4 + -1b = 0

Solving
-4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1b = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1b = 0 + 4
-1b = 0 + 4

Combine like terms: 0 + 4 = 4
-1b = 4

Divide each side by '-1'.
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(16 + -1b)' equal to zero and attempt to solve:

Simplifying
16 + -1b = 0

Solving
16 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -1b = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1b = 0 + -16
-1b = 0 + -16

Combine like terms: 0 + -16 = -16
-1b = -16

Divide each side by '-1'.
b = 16

Simplifying
b = 16
Solution
b = {-4, 16}